描述

对于给定的算术表达式，按规则输出计算结果，仅包含加法和大小判断。

输入

一行字符串，为加号、大于、小于( + < > ) 连接的两个不限大小的非负整数。

输出

当符号为 + 时, 计算两个数相加的和, 并以字符串格式返回； 当符号为 < 时, 如果左数小于右数, 返回大写字母字符 Y, 否则返回大写字母字符 N； 当符号为 > 时, 如果左数大于右数, 返回大写字母字符 Y, 否则返回大写字母字符 N。

!!!请同学们尽量使用算法来解决这个问题

输入样例

972919822976663297>74058
875098336507333719633571722631534917759993913379786689>53558270653237768027942884431075534537929401567824882097903948774409200
7625022925148127196027859399571498914361+790786706794530

输出样例

Y
N
7625022925148127196027860190358205708891

AC代码：

#include <bits/stdc++.h>
#include<vector>
#include<stack>
#include<sstream>
using namespace std;

string func1(string s1,string s2) //大于号
{
    if(s1.length()>s2.length())
    {
        return "Y";
    }
    else if(s1.length()<s2.length())
    {
        return "N";
    }
    else if(s1 == s2)
    {
        return "N";
    }
    else
    {
        int i = 0;
        while(i!=s1.length())
        {
            if((s1[i]-'0') > (s2[i]-'0'))
            {
                return "Y";
            }
            else if((s1[i]-'0') < (s2[i]-'0'))
            {
                return "N";
            }
            i++;
        }
    }
}

string func2(string s1,string s2) //小于号
{
    if(s1.length()>s2.length())
    {
        return "N";
    }
    else if(s1.length()<s2.length())
    {
        return "Y";
    }
    else if(s1 == s2)
    {
        return "N";
    }
    else
    {
        int i = 0;
        while(i!=s1.length())
        {
            if((s1[i]-'0') > (s2[i]-'0'))
            {
                return "N";
            }
            else if((s1[i]-'0') < (s2[i]-'0'))
            {
                return "Y";
            }
            i++;
        }
    }
}

string func3(string s1,string s2) //加号
{
    char temp;
    string result ="";
    bool flag = false;//判断是否有进位
    //已经默认s1>=s2
    while(s1.length()!=s2.length()){
        s2 = "0" + s2;
    }
    int i = s1.length()-1;
    while(i>=0)
    {
        stringstream ss;
        ss.clear();
        string temp = "";
        if(flag == false)
        {
            if((s1[i]-'0') + (s2[i]-'0') > 9)
            {
                flag = true;
                ss.clear();
                ss<<(((s1[i]-'0') + (s2[i]-'0'))-10);
                ss>>temp;
                result =temp + result;
            }
            else
            {
                flag = false;
                ss.clear();
                ss<<((s1[i]-'0') + (s2[i]-'0'));
                ss>>temp;
                result = temp + result;
            }
        }
        else
        {
            if((s1[i]-'0') + (s2[i]-'0')+1 > 9)
            {
                flag = true;
                ss.clear();
                ss<<(((s1[i]-'0') + (s2[i]-'0')+1)-10);
                ss>>temp;
                result =  temp+ result;
            }
            else
            {
                flag = false;
                ss.clear();
                ss<<((s1[i]-'0') + (s2[i]-'0')+1);
                ss>>temp;
                result = temp + result;
            }
        }
        i--;
    }
    if(flag == true)
        {
            result = "1" + result;
        }
    return result;
}

int main()
{
    string s="";
    while(cin>>s)
    {
        int mode = 0;
        string s1 = "";
        string s2 = "";
        for(int i = 0; i<s.length(); i++)
        {
            if(s[i] == '>' || s[i] =='<' ||s[i] =='+')
            {
                s1 = s.substr(0,i);
                s2 = s.substr(i+1,s.length()-i-1);
                if(s[i] == '>')
                {
                    mode = 1;
                }
                else if(s[i] == '<')
                {
                    mode = 2;
                }
                else if(s[i] == '+')
                {
                    mode = 3;
                }
                break;
            }

        }
        if(mode == 1)
        {
            cout<<func1(s1,s2)<<endl;
        }
        else if(mode == 2)
        {
            cout<<func2(s1,s2)<<endl;
        }
        else if(mode == 3)
        {
            if(func1(s1,s2) == "Y")
            {
                cout<<func3(s1,s2)<<endl;
            }
            else
            {
                cout<<func3(s2,s1)<<endl;
            }
        }
    }
}